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At a jump discontinuity in the square wave's Fourier series, what value does the partial sum approach?

At a point of discontinuity, the Fourier series converges to the midpoint of the one-sided limits. For the standard square wave jumping from -1 to 1 (or vice versa) at x=0x=0, the limit of the partial sums is −1+12=0\frac{-1 + 1}{2} = 0.

Conditions

  • The function satisfies Dirichlet conditions.
  • There is a finite jump discontinuity at the point of evaluation.

Reasoning, step by step

  1. Identify the left-hand limit f(x−)f(x^-) and right-hand limit f(x+)f(x^+) at the jump.
  2. Calculate the average: 12(f(x−)+f(x+))\frac{1}{2}(f(x^-) + f(x^+)).
  3. Compare this with the actual assigned value of the function at that point (which may be different).
  4. Conclude that the series converges to this average, not necessarily the function's defined value.

Example

The script states: 'At a jump they approach the midpoint, zero in this example.' The card adds: 'Values assigned at isolated jump points do not affect the Fourier coefficients.'

Common misconceptions

  • Expecting the Fourier series to converge to the exact value of the function at the discontinuity if it was defined there.
  • Thinking the series diverges at jumps.

Watch the explanation

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Answers are generated from source material and independently checked. Consult the original video or creator if something is unclear.