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How do you check that the argument of the sine function in the wave equation has consistent units?

To check the units of the sine argument kx−ωt+ϕkx-\omega t+\phi, assign the units of each variable: kk is in rad/m, xx is in m, ω\omega is in rad/s, tt is in s, and ϕ\phi is in rad. Multiply the units for kxkx and ωt\omega t to see that meters and seconds cancel out, leaving radians. Since all three terms reduce to radians, the argument is dimensionally consistent.

Conditions

  • Applies to the traveling sinusoidal wave equation y(x,t)=Asin⁡(kx−ωt+ϕ)y(x,t)=A\sin(kx-\omega t+\phi).
  • kk has units rad/m.
  • xx has units m.
  • ω\omega has units rad/s.
  • tt has units s.
  • ϕ\phi has units rad.

Reasoning, step by step

  1. Identify the argument of the sine function: kx−ωt+ϕkx-\omega t+\phi.
  2. Assign the unit rad/m to kk and m to xx.
  3. Assign the unit rad/s to ω\omega and s to tt.
  4. Assign the unit rad to ϕ\phi.
  5. Multiply the units of kk and xx: (rad/m) * m = rad.
  6. Multiply the units of ω\omega and tt: (rad/s) * s = rad.
  7. Conclude that each term in the argument carries units of radians, making the sine argument dimensionally consistent.

Example

The video displays a slide titled "Units" with the equation y(x,t)=Asin⁡(kx−ωt+ϕ)y(x,t)=A\sin(kx-\omega t+\phi). A purple box highlights the argument kx−ωt+ϕkx-\omega t+\phi, and unit labels rad/m, m, rad/s, s, and rad are written beneath the corresponding factors. The speaker explains that the meters and seconds cancel out, leaving radians minus radians plus radians, or just radians overall.

Common misconceptions

  • Assuming the sine function can accept arguments in degrees without conversion.
  • Forgetting that the phase constant ϕ\phi must also be in radians.
  • Thinking that the units of kk and ω\omega are dimensionless.

Watch the explanation

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Answers are generated from source material and independently checked. Consult the original video or creator if something is unclear.