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How do you convert coordinates from the standard basis to an alternative basis?

Use the inverse of the change-of-basis matrix PP. If PP converts from alternative to standard coordinates, then P−1P^{-1} converts from standard to alternative coordinates. For Jennifer's basis, P−1=[1/31/3−1/32/3]P^{-1}=\begin{bmatrix}1/3&1/3\\-1/3&2/3\end{bmatrix}, so applying it to (3,2)T(3,2)^T gives (5/3,1/3)T(5/3,1/3)^T.

Conditions

  • The change-of-basis matrix PP is invertible.
  • The input vector is given in standard coordinates.

Reasoning, step by step

  1. Compute or identify the inverse matrix P−1P^{-1}.
  2. Multiply P−1P^{-1} by the standard coordinate vector.
  3. The result is the vector's coordinates in the alternative basis.

Example

The script states: "The reverse conversion is P−1vP^{-1}v. Here P−1=[1/31/3−1/32/3]P^{-1}=\begin{bmatrix}1/3&1/3\\-1/3&2/3\end{bmatrix}, so applying it to (3,2)T(3,2)^T gives (5/3,1/3)T(5/3,1/3)^T."

Common misconceptions

  • Using PP instead of P−1P^{-1} for the reverse conversion.
  • Assuming that the inverse matrix is simply the transpose of PP (which is only true for orthogonal matrices).

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