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How do you derive the maximum-likelihood estimate for the rate parameter of independent exponential observations?

The maximum-likelihood estimate for the rate parameter λ\lambda is derived by maximizing the likelihood function λnexp⁡(−λ∑xi)\lambda^n \exp(-\lambda \sum x_i). The resulting estimate is n/∑xin / \sum x_i, which matches the moment estimate.

Conditions

  • The observations are independent.
  • The observations follow an exponential distribution.
  • The rate parameter λ\lambda is positive.

Reasoning, step by step

  1. Write the likelihood function for independent exponential observations: λnexp⁡(−λ∑xi)\lambda^n \exp(-\lambda \sum x_i).
  2. Maximize this likelihood function with respect to λ\lambda.
  3. Solve for the value of λ\lambda that maximizes the function.
  4. Obtain the maximum-likelihood estimate: n/∑xin / \sum x_i.
  5. Compare this estimate to the moment estimate, noting they are identical.

Example

The script states: 'For independent exponential observations with positive rate λ, the likelihood is λⁿexp(−λΣxᵢ). Its maximum gives n/Σxn/Σxᵢ, matching the moment estimate.'

Common misconceptions

  • Assuming the maximum-likelihood estimate and the moment estimate are always different.
  • Forgetting that the rate parameter λ\lambda must be positive.
  • Confusing the rate parameter λ\lambda with the mean parameter 1/λ1/\lambda.

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