How do you derive the maximum-likelihood estimate for the rate parameter of independent exponential observations?
Conditions
- The observations are independent.
- The observations follow an exponential distribution.
- The rate parameter is positive.
Reasoning, step by step
- Write the likelihood function for independent exponential observations: .
- Maximize this likelihood function with respect to .
- Solve for the value of that maximizes the function.
- Obtain the maximum-likelihood estimate: .
- Compare this estimate to the moment estimate, noting they are identical.
Example
The script states: 'For independent exponential observations with positive rate λ, the likelihood is λⁿexp(−λΣxᵢ). Its maximum gives ᵢ, matching the moment estimate.'
Common misconceptions
- Assuming the maximum-likelihood estimate and the moment estimate are always different.
- Forgetting that the rate parameter must be positive.
- Confusing the rate parameter with the mean parameter .
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Related questions
In a three-category model, the maximum-likelihood estimate for each probability is its observed count divided by the sample size. These estimates sum to one and respect the probability constraints.
Conditions: The model has three categories.; The estimates are derived using maximum likelihood.; The observed counts and sample size are known.
For a Uniform[0,θ] model, the maximum-likelihood estimate is the sample maximum, while the moment estimate is twice the sample mean. These two estimates need not agree because they are derived from different principles: the likelihood depends on the support covering every observation, whereas the moment estimate relies on the expected value.
Conditions: The model is Uniform[0,θ].; The parameter θ is positive.; Admissible parameter values must cover every observation.
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