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How do you reduce the coefficients of the polynomial f(x)=x4−x3+x2−2x+4f(x) = x^4 - x^3 + x^2 - 2x + 4 modulo 3 to find fˉ(x)\bar{f}(x)?

To find fˉ(x)\bar{f}(x), you reduce each coefficient of f(x)f(x) modulo 3. The coefficient of x4x^4 is 1, which remains 1. The coefficient of x3x^3 is -1, which is congruent to 2 mod 3. The coefficient of x2x^2 is 1, which remains 1. The coefficient of xx is -2, which is congruent to 1 mod 3. The constant term is 4, which is congruent to 1 mod 3. Thus, fˉ(x)=x4+2x3+x2+x+1\bar{f}(x) = x^4 + 2x^3 + x^2 + x + 1 in Z3[x]\mathbb{Z}_3[x].

Conditions

  • The polynomial is f(x)=x4−x3+x2−2x+4f(x) = x^4 - x^3 + x^2 - 2x + 4.
  • Coefficients are reduced modulo 3.

Reasoning, step by step

  1. Identify the coefficient of x4x^4 as 1, which is 1(mod3)1 \pmod 3.
  2. Identify the coefficient of x3x^3 as -1, which is 2(mod3)2 \pmod 3.
  3. Identify the coefficient of x2x^2 as 1, which is 1(mod3)1 \pmod 3.
  4. Identify the coefficient of xx as -2, which is 1(mod3)1 \pmod 3.
  5. Identify the constant term as 4, which is 1(mod3)1 \pmod 3.
  6. Construct the new polynomial fˉ(x)=x4+2x3+x2+x+1\bar{f}(x) = x^4 + 2x^3 + x^2 + x + 1.

Example

The narrator states, 'The coefficient for x to the fourth is 1... For x cubed, it's negative 1, which is congruent to 2 mod 3... For x squared, it's 1... For x, it's negative 2, which is congruent to 1 mod 3. And the constant term is 4, which is 1 mod 3.'

Common misconceptions

  • Assuming negative coefficients remain negative in Z3\mathbb{Z}_3 instead of converting them to positive equivalents (e.g., -1 to 2).
  • Forgetting to reduce the constant term modulo 3.

Watch the explanation

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