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How do you verify that an ordered pair solves a linear equation with fractions?

To verify an ordered pair solves a linear equation with fractions, substitute the xx and yy values into the left-hand side of the equation. Evaluate the products by multiplying each fraction by its corresponding integer. Find a common denominator for the resulting fractions, rewrite them as equivalent fractions, subtract or add the numerators, reduce the final fraction to lowest terms, and check if it equals the right-hand side of the original equation.

Conditions

  • The candidate solution values must already be known.
  • The equation being checked contains those variables with fractional coefficients.

Reasoning, step by step

  1. Substitute the known values of xx and yy into the left-hand side of the equation.
  2. Multiply each fraction by its corresponding integer value (multiply the numerator, keep the denominator).
  3. Identify that the resulting fractions have different denominators and cannot be combined directly.
  4. Find the least common multiple of the denominators to use as a common denominator.
  5. Rewrite each fraction as an equivalent fraction with the common denominator by multiplying numerator and denominator by the appropriate factor (a form of 1).
  6. Perform the addition or subtraction on the numerators while keeping the common denominator.
  7. Reduce the resulting fraction to lowest terms by dividing numerator and denominator by their greatest common factor.
  8. Compare the simplified result to the right-hand side of the original equation. If they are equal, the solution is verified.

Example

To check (2,−2)(2, -2) in 34x+15y=1110\frac{3}{4}x + \frac{1}{5}y = \frac{11}{10}: substitute to get 34(2)+15(−2)=64−25\frac{3}{4}(2) + \frac{1}{5}(-2) = \frac{6}{4} - \frac{2}{5}. The common denominator of 4 and 5 is 20. Rewrite: 64⋅55=3020\frac{6}{4} \cdot \frac{5}{5} = \frac{30}{20} and 25⋅44=820\frac{2}{5} \cdot \frac{4}{4} = \frac{8}{20}. Subtract: 3020−820=2220\frac{30}{20} - \frac{8}{20} = \frac{22}{20}. Reduce: 2220=1110\frac{22}{20} = \frac{11}{10}. Since 1110=1110\frac{11}{10} = \frac{11}{10}, the solution is correct.

Common misconceptions

  • Attempting to subtract fractions with unlike denominators directly without first finding a common denominator.
  • Believing that rewriting a fraction with a different denominator (e.g., 64\frac{6}{4} to 3020\frac{30}{20}) changes its value.
  • Forgetting to reduce the final fraction to lowest terms before comparing it to the right-hand side.

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