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How does Rolle's theorem relate to the mean value theorem?

Rolle's theorem is a special case of the mean value theorem. It applies when the function values at the endpoints are equal, i.e., f(a)=f(b)f(a) = f(b). In this scenario, the average rate of change f(b)−f(a)b−a\frac{f(b)-f(a)}{b-a} becomes zero. Consequently, the mean value theorem guarantees the existence of a point cc in (a,b)(a,b) where the derivative f′(c)f'(c) is zero, corresponding to a horizontal tangent.

Conditions

  • ff is continuous on [a,b][a,b]
  • ff is differentiable on (a,b)(a,b)
  • f(a)=f(b)f(a) = f(b)

Reasoning, step by step

  1. Start with the general mean value theorem formula: f′(c)=f(b)−f(a)b−af'(c) = \frac{f(b)-f(a)}{b-a}.
  2. Apply the additional condition f(a)=f(b)f(a) = f(b).
  3. Calculate the numerator: f(b)−f(a)=0f(b) - f(a) = 0.
  4. Determine that the average rate of change is zero.
  5. Conclude that there exists c∈(a,b)c \in (a,b) such that f′(c)=0f'(c) = 0.
  6. Interpret f′(c)=0f'(c)=0 geometrically as a horizontal tangent.

Example

If a function starts and ends at the same height on an interval, Rolle's theorem ensures there is at least one peak or valley (horizontal tangent) in between.

Common misconceptions

  • Thinking Rolle's theorem requires the function to be monotonic.
  • Believing that the point cc must be a maximum or minimum (it is a critical point, but could be an inflection point with horizontal tangent).

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