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How does the limiting process convert the discrete sum of ring areas into the continuous area of a triangle?

By placing strips of height 2πr2\pi r along the radius axis, their tops form a linear graph. As the partition width goes to zero, the step-function approximation converges to the area under the line y=2πxy=2\pi x. This region is a right triangle with base RR and height 2πR2\pi R, yielding area 12⋅R⋅2πR=πR2\frac{1}{2} \cdot R \cdot 2\pi R = \pi R^2.

Conditions

  • Function f(r)=2πrf(r) = 2\pi r is linear
  • Partition width Δr→0\Delta r \to 0

Reasoning, step by step

  1. Arrange the rectangular strips side-by-side along the horizontal axis representing radius rr.
  2. Note that the height of each strip corresponds to the circumference 2πri2\pi r_i.
  3. Observe that as Δr\Delta r shrinks, the jagged top edge of the rectangles smooths out.
  4. Identify the limiting shape formed by the tops of the strips as a straight line passing through the origin.
  5. Calculate the area of the resulting geometric figure: a triangle with vertices at (0,0)(0,0), (R,0)(R,0), and (R,2πR)(R, 2\pi R).
  6. Apply the triangle area formula: Area=12×base×height\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}.

Example

The script explains: 'Place the strips along the radius axis with heights 2πr... As maximum partition width tends to zero, the sums approach the area beneath the linear circumference function... The limiting region is a triangle with base R and height 2πR, giving πR².'

Common misconceptions

  • Confusing the area of the rectangle bounding box (2πR22\pi R^2) with the actual triangular area (πR2\pi R^2).
  • Assuming the limit applies only to the height, not the arrangement of the strips.

Watch the explanation

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