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What does the condition alpha_1^2 + alpha_2^2 != 0 mean in the boundary condition?

For real constants, the condition α12+α22≠0\alpha_1^2 + \alpha_2^2 \neq 0 is a compact way to state that α1\alpha_1 and α2\alpha_2 are not both zero. This ensures that the boundary condition at the endpoint x=ax=a is nontrivial. Similarly, β12+β22≠0\beta_1^2 + \beta_2^2 \neq 0 means β1\beta_1 and β2\beta_2 are not both zero.

Conditions

  • The constants α1,α2\alpha_1, \alpha_2 are real numbers.
  • The boundary condition is α1y(a)+α2y′(a)=0\alpha_1 y(a) + \alpha_2 y'(a) = 0.

Reasoning, step by step

  1. Recognize that the sum of squares of two real numbers is zero if and only if both numbers are zero.
  2. Apply this to α12+α22≠0\alpha_1^2 + \alpha_2^2 \neq 0 to conclude that α1\alpha_1 and α2\alpha_2 cannot both be zero.
  3. Understand that this prevents the boundary condition from becoming the trivial equation 0=00 = 0.

Example

The board writes α12+α22≠0\alpha_1^2 + \alpha_2^2 \neq 0 and β12+β22≠0\beta_1^2 + \beta_2^2 \neq 0. The lecturer says this is shorthand for saying alpha one and alpha two are not both zero.

Common misconceptions

  • Thinking the condition imposes a special quantitative restriction beyond excluding the zero pair.
  • Assuming that either coefficient in a boundary condition must be nonzero; one coefficient may be zero, but not both at the same endpoint.

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