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What is the actual increment Δz of a two-variable function when the input is displaced by (Δx, Δy)?

The actual increment Δz\Delta z is the difference between the new function value and the reference function value after the input is displaced. It is calculated as Δz=f(x0+Δx,y0+Δy)−f(x0,y0)\Delta z = f(x_0+\Delta x, y_0+\Delta y) - f(x_0, y_0). It represents the true change in height on the curved surface, measured relative to the reference height.

Conditions

  • The function is evaluated at a reference point (x0,y0)(x_0, y_0).
  • The input is moved by a displacement (Δx,Δy)(\Delta x, \Delta y).

Reasoning, step by step

  1. Identify the reference input (x0,y0)(x_0, y_0) and the displacement (Δx,Δy)(\Delta x, \Delta y).
  2. Calculate the new function value at the displaced input: f(x0+Δx,y0+Δy)f(x_0+\Delta x, y_0+\Delta y).
  3. Retrieve the reference function value: f(x0,y0)f(x_0, y_0).
  4. Subtract the reference value from the new value to find the actual increment: Δz=f(x0+Δx,y0+Δy)−f(x0,y0)\Delta z = f(x_0+\Delta x, y_0+\Delta y) - f(x_0, y_0).

Example

The script states: 'Move the input by (Δx,Δy). The actual increment Δz is the new function value minus its reference value.' The card formula is Δz=f(x0+Δx,y0+Δy)−f(x0,y0)\Delta z = f(x_0+\Delta x, y_0+\Delta y) - f(x_0, y_0).

Common misconceptions

  • Confusing the actual increment Δz\Delta z with the total differential dzdz, which is the tangent plane's height change.
  • Believing that Δz\Delta z represents the absolute height above the xy-plane rather than the change in height relative to the reference point.
  • Assuming that Δz\Delta z is always equal to dzdz; they are only equal if the surface is a plane.

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