Skip to content
← All questions

What is the determinant of matrix A in this example?

The determinant of matrix AA in this example is −1-1. This value is obtained by expanding the determinant along the first row of the matrix A=[13−225−3−32−4]A=\begin{bmatrix}1&3&-2\\2&5&-3\\-3&2&-4\end{bmatrix}. The calculation confirms that det⁡(A)≠0\det(A) \neq 0, which establishes that the matrix is invertible.

Conditions

  • A is the specific 3x3 matrix given in the problem.
  • The determinant is calculated using cofactor expansion along the first row.

Reasoning, step by step

  1. Identify the first row of matrix A: 1, 3, -2.
  2. Calculate the minor determinants for each element in the first row.
  3. Apply the alternating signs (+, -, +) to the minors.
  4. Sum the products of the row elements and their signed minors.
  5. The result is det⁡(A)=−1\det(A) = -1.

Example

The screen displays the expansion: det⁡(A)=1∣5−32−4∣−3∣2−3−3−4∣+(−2)∣25−32∣=−1≠0\det(A)=1\begin{vmatrix}5&-3\\2&-4\end{vmatrix}-3\begin{vmatrix}2&-3\\-3&-4\end{vmatrix}+(-2)\begin{vmatrix}2&5\\-3&2\end{vmatrix}=-1\neq 0.

Common misconceptions

  • Calculating the determinant incorrectly due to sign errors in the cofactor expansion.
  • Assuming the determinant is positive because the matrix elements are mostly positive.
  • Forgetting to check if the determinant is zero before proceeding to find the inverse.

Watch the explanation

Connected concepts

Explore next

Related questions

Find a method

↗
Meet the concept

↗
Meet the concept

↗
Understand why

↗

Answers are generated from source material and independently checked. Consult the original video or creator if something is unclear.