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What is the Lagrangian used in the Euler-Lagrange equation for F?

The Lagrangian L\mathscr{L} used to minimize the integral FF via the Euler-Lagrange equation is L=gijx˙ix˙j\mathscr{L} = g_{ij}\dot{x}^i\dot{x}^j. This is the integrand of the functional FF.

Conditions

  • Applied to the integral FF.
  • x˙i\dot{x}^i and x˙j\dot{x}^j are derivatives with respect to λ\lambda.
  • gijg_{ij} are metric components.

Reasoning, step by step

  1. Identify the functional F=∫ABgijx˙ix˙j dλF = \int_A^B g_{ij}\dot{x}^i\dot{x}^j\,d\lambda.
  2. Extract the integrand as the Lagrangian L=gijx˙ix˙j\mathscr{L} = g_{ij}\dot{x}^i\dot{x}^j.
  3. Apply the Euler-Lagrange equation to this L\mathscr{L}.
  4. Derive the geodesic equation.

Example

The video states: "for the case of the integral F the Lagrangian is given by this" and displays L=gijx˙ix˙j\mathscr{L} = g_{ij}\dot{x}^i\dot{x}^j.

Common misconceptions

  • Confusing the Lagrangian L\mathscr{L} with the functional FF; FF is the integral of L\mathscr{L}.
  • Assuming the Lagrangian includes the square root; it does not, because we are minimizing FF, not LL.

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Answers are generated from source material and independently checked. Consult the original video or creator if something is unclear.