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What is the mathematical iteration formula for Newton's method?

The mathematical iteration formula for Newton's method is xn+1=xn−f(xn)f′(xn)x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)}. This formula updates the current guess xnx_n to the next guess xn+1x_{n+1} by subtracting the ratio of the function value to its derivative.

Conditions

  • f′(xn)f'(x_n) must be available and nonzero for the displayed division.
  • The formula gives one iterative update from xnx_n to xn+1x_{n+1}.

Reasoning, step by step

  1. Identify the current iterate xnx_n.
  2. Evaluate the function at the current iterate, f(xn)f(x_n).
  3. Evaluate the derivative of the function at the current iterate, f′(xn)f'(x_n).
  4. Calculate the correction term f(xn)f′(xn)\frac{f(x_n)}{f'(x_n)}.
  5. Subtract the correction term from the current iterate to get the next iterate xn+1x_{n+1}.

Example

The video displays the formula xn+1=xn−f(xn)f′(xn)x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)} as the algebraic summary of the tangent-line construction.

Common misconceptions

  • Forgetting the negative sign in the formula.
  • Assuming the formula works if the derivative is zero; division by zero is undefined.

Watch the explanation

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Answers are generated from source material and independently checked. Consult the original video or creator if something is unclear.