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What is the resultant amplitude when two equal-frequency sinusoids with an arbitrary phase difference are superposed?

Adding equal-frequency sinusoids produces a sinusoid at the same frequency. Its amplitude lies between the absolute difference and the sum of the individual amplitudes, calculated by the formula A=A12+A22+2A1A2cos⁡ϕA=\sqrt{A_1^2+A_2^2+2A_1A_2\cos\phi}, where ϕ\phi is the phase difference.

Conditions

  • The two waves have the same frequency.
  • The two waves have an arbitrary phase difference ϕ\phi.

Reasoning, step by step

  1. Identify the amplitudes A1A_1 and A2A_2 of the two individual waves.
  2. Determine the phase difference ϕ\phi between the two waves.
  3. Apply the formula A=A12+A22+2A1A2cos⁡ϕA=\sqrt{A_1^2+A_2^2+2A_1A_2\cos\phi} to calculate the resultant amplitude.

Example

The bottom coordinate system demonstrates superposition with an arbitrary phase difference. The blue wave (A=2A=2) combines with a phase-shifted red wave (A=0.8A=0.8), producing a green wave that exhibits changes in both amplitude and phase position.

Common misconceptions

  • Believing that the resultant amplitude is always the sum of the individual amplitudes.
  • Assuming that the phase difference only affects the position of the wave, not its amplitude.

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