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Why is every product Ax a member of the column space C(A)C(A)?

Every product Ax⃗A\vec{x} is a member of the column space C(A)C(A) because matrix-vector multiplication is defined as a linear combination of the columns of AA. Specifically, if A=[a⃗1 a⃗2 ⋯ a⃗k]A = [\vec{a}_1 \ \vec{a}_2 \ \cdots \ \vec{a}_k] and x⃗=[x1,…,xk]T\vec{x} = [x_1, \dots, x_k]^T, then Ax⃗=x1a⃗1+⋯+xka⃗kA\vec{x} = x_1\vec{a}_1 + \dots + x_k\vec{a}_k. Since C(A)C(A) is the set of all such linear combinations, any output Ax⃗A\vec{x} must lie within C(A)C(A).

Conditions

  • AA is an n×kn \times k matrix
  • x⃗∈Rk\vec{x} \in \mathbb{R}^k
  • C(A)C(A) is the span of the columns of AA

Reasoning, step by step

  1. Expand the matrix AA into its column vectors a⃗1,…,a⃗k\vec{a}_1, \dots, \vec{a}_k.
  2. Write the vector x⃗\vec{x} in terms of its components x1,…,xkx_1, \dots, x_k.
  3. Apply the definition of matrix-vector multiplication: Ax⃗=x1a⃗1+x2a⃗2+⋯+xka⃗kA\vec{x} = x_1\vec{a}_1 + x_2\vec{a}_2 + \cdots + x_k\vec{a}_k.
  4. Recognize that this expression is a linear combination of the columns of AA.
  5. Conclude that by definition, any linear combination of the columns belongs to the column space C(A)C(A).

Example

The speaker writes v=Ax⃗∗v = A\vec{x}^* and places vv inside the purple plane labeled C(A)C(A), stating explicitly that 'Ax is going to be a member of my column space'.

Common misconceptions

  • Thinking that Ax⃗A\vec{x} can produce a vector outside the span of AA's columns.
  • Confusing the column space with the domain of x⃗\vec{x}.

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