Why is the factor grouped with the square root in the split of √()?
Conditions
- The integrand is .
- The method involves integration by parts.
- The term must be integrable.
Reasoning, step by step
- Identify the composite part .
- Check the derivative of the inside: .
- Notice that is needed for the substitution to work.
- Split into .
- Group with the square root to form .
- Leave as for differentiation.
Example
The script states: 'Choosing the first factor for differentiation makes the second factor integrable with a substitution.' The second factor is .
Common misconceptions
- Grouping entirely with the square root, making it hard to integrate.
- Grouping with , leaving as which is not easily integrable.
- Forgetting that substitution requires the derivative of the inner function to be present.
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