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Why is the factor x3x^3 grouped with the square root in the split of x7x^7√(1+x41+x^4)?

The factor x3x^3 is grouped with 1+x4\sqrt{1+x^4} because the derivative of the inner function 1+x41+x^4 is 4x34x^3. This presence of x3x^3 makes the expression x31+x4x^3\sqrt{1+x^4} directly integrable using substitution, which is a prerequisite for the integration by parts method.

Conditions

  • The integrand is x71+x4x^7\sqrt{1+x^4}.
  • The method involves integration by parts.
  • The term dvdv must be integrable.

Reasoning, step by step

  1. Identify the composite part 1+x4\sqrt{1+x^4}.
  2. Check the derivative of the inside: d(1+x4)=4x3dxd(1+x^4) = 4x^3 dx.
  3. Notice that x3x^3 is needed for the substitution to work.
  4. Split x7x^7 into x4⋅x3x^4 \cdot x^3.
  5. Group x3x^3 with the square root to form dvdv.
  6. Leave x4x^4 as uu for differentiation.

Example

The script states: 'Choosing the first factor for differentiation makes the second factor integrable with a substitution.' The second factor is x31+x4x^3\sqrt{1+x^4}.

Common misconceptions

  • Grouping x7x^7 entirely with the square root, making it hard to integrate.
  • Grouping x3x^3 with x4x^4, leaving 1+x4\sqrt{1+x^4} as dvdv which is not easily integrable.
  • Forgetting that substitution requires the derivative of the inner function to be present.

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