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Why is the likelihood function not a probability distribution?

The likelihood function is not a probability distribution because its integral over the parameter space does not equal 1. It measures how well each parameter value explains the fixed data, rather than assigning probabilities to the parameter values themselves.

Conditions

  • The data are fixed.
  • The parameter pp is varied over its space [0,1][0,1].

Reasoning, step by step

  1. Define the likelihood function L(p)L(p) for fixed data.
  2. Compute the integral of L(p)L(p) over the parameter range p∈[0,1]p \in [0,1].
  3. Observe that ∫01L(p) dp≠1\int_0^1 L(p)\,dp \neq 1.
  4. Conclude that because it lacks normalization, L(p)L(p) is not a probability distribution over pp.

Example

The video shades the area under the likelihood curve and displays the inequality ∫01L(p) dp≠1\int_0^1 L(p)\,dp \neq 1 alongside the caption "Not a probability distribution!" to demonstrate that the area does not sum to 1.

Common misconceptions

  • Assuming that any curve resembling a bell shape must be a probability distribution.
  • Thinking that the height of the likelihood curve at a specific pp gives the probability that pp is the true parameter.

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