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Answers for “为什么在换元中匹配导数很重要?”

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The substitution x=1+eux = 1 + e^u simplifies the integrand because its derivative dx=eududx = e^u du exactly matches the eudue^u du term in the original integral. This allows the complex expression eu1+eudue^u \sqrt{1+e^u} du to be rewritten as the simpler radical xdx\sqrt{x} dx.

Conditions: The integrand contains eu1+eue^u \sqrt{1+e^u}.; The substitution is x=1+eux = 1 + e^u.; The differential is dx=eududx = e^u du.