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Answers for “为什么欧几里得算法将旧的除数和余数移入下一行?”

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To start the Euclidean algorithm for gcd⁡(10,45)\gcd(10,45), you write the larger number as the smaller number multiplied by an unknown quotient plus an unknown remainder. Specifically, you set up the division equation 45=10⋅q+r45 = 10 \cdot q + r.

Conditions: The inputs are positive integers.; The larger number is placed on the left-hand side of the equation.; The quotient is an integer and the remainder satisfies 0≤r<100 \le r < 10.

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In the Euclidean algorithm, the previous divisor becomes the new dividend (placed on the left side of the equation), and the previous remainder becomes the new divisor (placed on the right side). This recursive shift carries the numbers forward so that each step divides the former divisor by the former remainder, continuing until a remainder of zero is reached.

Conditions: The algorithm is applied to positive integers.; The previous remainder is not zero.; The process follows the standard division-with-remainder format a=b⋅q+ra = b \cdot q + r.