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Answers for “在复分析中,函数是解析的有什么后果?”

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The proof relies on the fact that each partial sum fn(s)=∑k=1n1ksf_n(s) = \sum_{k=1}^n \frac{1}{k^s} is a finite sum of analytic functions, making fn(s)f_n(s) itself analytic. The lecture previously established that fn(s)f_n(s) converges uniformly to ζ(s)\zeta(s) on any closed half-plane Re⁡(s)≥1+a\operatorname{Re}(s)\ge 1+a for a>0a>0.

Conditions: fn(s)f_n(s) are the partial sums of the zeta series.; The Uniform Limit Theorem applies to sequences of analytic functions converging uniformly on a domain.; aa is an arbitrarily small positive constant (a>0a>0).