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To verify the base case, substitute $n=1$ into both sides of the equation. The left-hand side (LHS) becomes the first term, 2.

Conditions: The proposition is $P(n)$: $2 + 4$ + ... + $2n = n(n+1)$.; The base case is checked at $n=1$.

To verify the base case, substitute $n=1$ into both sides of the equation. The left-hand side (LHS) becomes the first term, 2.

Conditions: The proposition is $P(n)$: $2 + 4$ + ... + $2n = n(n+1)$.; The base case is checked at $n=1$.