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Answers for “如何逐项展开求和式 $\sum_{k=0}^{\infty}\frac{(-1)^k x^{2k}}{(2k)!}$?”

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To expand the summation, substitute successive integer values for the index kk into the general term. For k=0k=0, the term simplifies to 11.

Conditions: The summation index kk starts at 00 and increases by 11 for each term.; The general term is (−1)kx2k(2k)!\frac{(-1)^k x^{2k}}{(2k)!}.