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In a sample space of nine equally likely outcomes, let event A contain 5 elements and event B contain 6 elements, with their intersection containing 2 elements. The conditional probability $P(A \mid B)$ is calculated directly as the size of the intersection divided by the size of B: $2/6 = 1/3$.

Conditions: The sample space has nine equally likely outcomes.; Event A has 5 elements, Event B has 6 elements, and $A \cap B$ has 2 elements.

In a sample space of nine equally likely outcomes, let event A contain 5 elements and event B contain 6 elements, with their intersection containing 2 elements. The conditional probability $P(A \mid B)$ is calculated directly as the size of the intersection divided by the size of B: $2/6 = 1/3$.

Conditions: The sample space has nine equally likely outcomes.; Event A has 5 elements, Event B has 6 elements, and $A \cap B$ has 2 elements.