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Answers for “共振试探解 $Ate^{-t}$ 的一阶和二阶导数是什么?”

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The first segment stops after computing the first and second derivatives of the resonant trial solution x=Ate−tx=Ate^{-t}. It does not yet substitute these derivatives back into the differential equation or solve for the unknown coefficient AA.

Conditions: The segment covers the setup of the homogeneous solution and the resonant trial solution.; The derivatives x˙\dot{x} and x¨\ddot{x} are computed but not substituted.