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The simplified derivative is $\sin(t^{5/2})/(2t^{5/2})$. This is obtained by evaluating the integrand at $x=\sqrt{t}$ and multiplying by the derivative of the upper limit, $1/(2\sqrt{t})$.

Conditions: The integrand is $\sin(x^5)/x^4$.; The lower limit is the constant 2.; The upper limit is $\sqrt{t}$.; $t > 0$.

The simplified derivative is $\sin(t^{5/2})/(2t^{5/2})$. This is obtained by evaluating the integrand at $x=\sqrt{t}$ and multiplying by the derivative of the upper limit, $1/(2\sqrt{t})$.

Conditions: The integrand is $\sin(x^5)/x^4$.; The lower limit is the constant 2.; The upper limit is $\sqrt{t}$.; $t > 0$.

The notation $\frac{d}{dx}f(-2)$ represents evaluating the derivative of the function $f$ specifically at the horizontal input coordinate $x = -2$. It denotes the instantaneous slope of the tangent line to the graph at that exact abscissa, rather than referring to a point where the output or function value happens to be $-2$.

Conditions: The expression evaluates the derivative operator applied to the function $f$.; The argument inside the parentheses is strictly the independent variable (input $x$).

The notation $\frac{d}{dx}f(-2)$ represents evaluating the derivative of the function $f$ specifically at the horizontal input coordinate $x = -2$. It denotes the instantaneous slope of the tangent line to the graph at that exact abscissa, rather than referring to a point where the output or function value happens to be $-2$.

Conditions: The expression evaluates the derivative operator applied to the function $f$.; The argument inside the parentheses is strictly the independent variable (input $x$).

For the arc length formula $\int_{a}^{b} \sqrt{1 + (f'(x))^2} dx$ to be valid, the function $f(x)$ must be continuous on the closed interval $[a, b]$, and its derivative $f'(x)$ must also be continuous on $[a, b]$. These conditions ensure that the curve is smooth enough for the integral to accurately represent its length.

Conditions: The curve is defined by a function $y = f(x)$.; The interval of integration is $[a, b]$.; $f(x)$ is continuous on $[a, b]$.; $f'(x)$ is continuous on $[a, b]$.

For the arc length formula $\int_{a}^{b} \sqrt{1 + (f'(x))^2} dx$ to be valid, the function $f(x)$ must be continuous on the closed interval $[a, b]$, and its derivative $f'(x)$ must also be continuous on $[a, b]$. These conditions ensure that the curve is smooth enough for the integral to accurately represent its length.

Conditions: The curve is defined by a function $y = f(x)$.; The interval of integration is $[a, b]$.; $f(x)$ is continuous on $[a, b]$.; $f'(x)$ is continuous on $[a, b]$.