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Answers for “两个笛卡尔积的交集是什么?”

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The intersection of two Cartesian products (A×BA \times B) and (C×DC \times D) is equal to the Cartesian product of the intersections of their respective component sets, i.e., (A ∩ C) × (B ∩ D).

Conditions: A, B, C, and D are arbitrary sets.

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The Cartesian product distributes over both union and intersection from both the left and the right. Specifically, (A ∪ B) × C=(A×C)C = (A \times C) ∪ (B×CB \times C), (A ∩ B) × C=(A×C)C = (A \times C) ∩ (B×CB \times C), A × (B ∪ C) = (A×BA \times B) ∪ (A×CA \times C), and A × (B ∩ C) = (A×BA \times B) ∩ (A×CA \times C).

Conditions: A, B, and C are arbitrary sets.

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The Cartesian product of two sets A and B, denoted A×BA \times B, is the set of all possible ordered pairs (x, y) where the first element x belongs to set A and the second element y belongs to set B.

Conditions: A and B are arbitrary sets.