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Answers for “共振试探解 $Ate^{-t}$ 的一阶和二阶导数是什么?”

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The first derivative is x˙=Ae−t(1−t)\dot{x}=Ae^{-t}(1-t), and the second derivative is x¨=Ae−t(t−2)\ddot{x}=Ae^{-t}(t-2). These are computed by applying the product rule successively to the trial solution x=Ate−tx=Ate^{-t}.

Conditions: The trial solution is x=Ate−tx=Ate^{-t}.; Differentiation is with respect to tt.; The product rule is applied to tt and e−te^{-t}.