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The final equation of the secant line intersecting the curve $y = x^2 - 4$ at $x = -1$ and $x = 2$ is $y = x - 2$. This result is derived by calculating the slope $m = 1$ between the points $(-1, -3)$ and $(2, 0)$, then applying the point-slope formula and simplifying to slope-intercept form.

Conditions: The curve is $y = x^2 - 4$.; The secant line intersects the curve at $x = -1$ and $x = 2$.; The equation is expressed in slope-intercept form ($y = mx + b$).

The final equation of the secant line intersecting the curve $y = x^2 - 4$ at $x = -1$ and $x = 2$ is $y = x - 2$. This result is derived by calculating the slope $m = 1$ between the points $(-1, -3)$ and $(2, 0)$, then applying the point-slope formula and simplifying to slope-intercept form.

Conditions: The curve is $y = x^2 - 4$.; The secant line intersects the curve at $x = -1$ and $x = 2$.; The equation is expressed in slope-intercept form ($y = mx + b$).