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Answers for “如果基周期是 2π,cos(2t) 的频率是多少?”

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If the base period is 2π2\pi, the term cos⁡(t)\cos(t) has a frequency of 12π\frac{1}{2\pi} cycles per second. Doubling the argument to cos⁡(2t)\cos(2t) doubles the frequency, so cos⁡(2t)\cos(2t) has a frequency of 1π\frac{1}{\pi} cycles per second.

Conditions: The base period of the function is 2π2\pi.; The frequency is defined as the reciprocal of the period.