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Answers for “常微分方程 $\ddot{x}+3\dot{x}+2x=2e^{-t}$ 的最终特解是什么?”

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The final particular solution is Xp(t)=2te−tX_p(t) = 2te^{-t}. This is obtained by substituting the solved coefficient A=2A=2 back into the resonant trial solution x=Ate−tx=Ate^{-t}.

Conditions: The ODE is x¨+3x˙+2x=2e−t\ddot{x}+3\dot{x}+2x=2e^{-t}.; The coefficient AA has been determined to be 22.; The trial solution form is x=Ate−tx=Ate^{-t}.