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Answers for “为什么余数总是小于 $b$?”

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The Euclidean algorithm terminates because the remainder in each step is strictly smaller than the previous divisor. Since the second argument is a nonnegative integer that decreases with each step, it must eventually reach zero.

Conditions: The algorithm operates on nonnegative integers.; Each step replaces the pair (a,b)(a,b) with (b,a mod b)(b, a\bmod b).; The remainder a mod ba\bmod b is strictly less than bb when b>0b > 0.

Understand why

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By the definition of division with remainder, for any integers aa and bb (b>0b>0), there exist unique integers qq and rr such that a=bq+ra = bq + r and 0≤r<b0 \le r < b. This constraint on rr ensures that the remainder is always strictly smaller than the divisor bb, which is crucial for the algorithm's termination.

Conditions: bb is a positive integer.; aa is a nonnegative integer.; The operation is a mod ba \bmod b.