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Answers for “为什么在一般的局部化设置中,朴素的交叉相乘条件是不够的?”

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The naive condition r1s2=s1r2r_1s_2 = s_1r_2 is insufficient because in a general commutative ring, elements can be annihilated by nonzero elements of SS. The refined condition requires the existence of some t∈St \in S such that t(r1s2−s1r2)=0t(r_1s_2 - s_1r_2) = 0, which accounts for zero-divisor phenomena and ensures the equivalence relation is well-defined.

Conditions: RR is a general commutative ring (not necessarily an integral domain).; S⊂RS \subset R is multiplicatively closed.