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Answers for “尾和 R_n(s) 如何用于证明一致收敛?”

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The lecture restricts the proof to the region Re⁡(s)≥1+a\operatorname{Re}(s)\ge 1+a (with a fixed a>0a>0) to avoid the singularity at Re⁡(s)=1\operatorname{Re}(s)=1. Near this boundary, the zeta function blows up, which prevents the partial sums from converging uniformly across the entire open half-plane Re⁡(s)>1\operatorname{Re}(s)>1.

Conditions: aa is a fixed positive constant (a>0a>0).; The region of interest is the closed half-plane Re⁡(s)≥1+a\operatorname{Re}(s)\ge 1+a.; The full defining region of the zeta series is Re⁡(s)>1\operatorname{Re}(s)>1.