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Answers for “上限的导数是什么?”

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Meet the concept

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The derivative of the upper limit u=tu=\sqrt{t} with respect to tt is 1/(2t)1/(2\sqrt{t}). This factor is used in the chain rule when differentiating an integral with this variable upper limit.

Conditions: t>0t > 0.; The upper limit is defined as u=tu=\sqrt{t}.

Meet the concept

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The simplified derivative is sin⁡(t5/2)/(2t5/2)\sin(t^{5/2})/(2t^{5/2}). This is obtained by evaluating the integrand at x=tx=\sqrt{t} and multiplying by the derivative of the upper limit, 1/(2t)1/(2\sqrt{t}).

Conditions: The integrand is sin⁡(x5)/x4\sin(x^5)/x^4.; The lower limit is the constant 2.; The upper limit is t\sqrt{t}.; t>0t > 0.

Understand why

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The factor is essential because the Fundamental Theorem of Calculus combined with the Chain Rule requires multiplying the integrand evaluated at the upper limit by the derivative of that limit. Without this factor, the rate of change of the accumulated area with respect to the outer variable tt would be incorrect.

Conditions: The upper limit is a function of tt, not just tt itself.; The integrand is continuous.

Meet the concept

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The net-change formula states that for a continuously differentiable function on an interval, integrating its derivative gives the endpoint difference. Specifically, the integral of the derivative f′f' from aa to bb equals f(b)−f(a)f(b) - f(a).

Conditions: The function is continuously differentiable on the interval.; The integration is over the interval from aa to bb.

Find a method

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To differentiate an integral with a square-root upper limit, you evaluate the integrand at the upper limit and multiply by the derivative of that limit. For an upper limit u=tu=\sqrt{t}, the derivative is 1/(2t)1/(2\sqrt{t}).

Conditions: The integrand is continuous on the relevant interval.; The upper limit is a differentiable function of tt, specifically u=tu=\sqrt{t}.; t>0t > 0.

Know when to use it

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This occurs when the integrand is continuous on the relevant interval. Under this condition, the Fundamental Theorem of Calculus states that the derivative of the integral with respect to its upper limit is the integrand evaluated at that limit.

Conditions: The integrand is continuous on the interval of integration.; The upper endpoint is the variable with respect to which we are differentiating (before applying the chain rule for a composite limit).