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Answers for “为什么余数小于 $b$ 能使重复的步骤终止?”

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The Euclidean algorithm keeps the GCD by repeatedly applying the step gcd⁡(a,b)=gcd⁡(b,a mod b)\gcd(a,b)=\gcd(b,a\bmod b) for nonnegative aa and positive bb. This replaces the pair with the divisor and the remainder, preserving the greatest common divisor.

Conditions: aa is a nonnegative integer.; bb is a positive integer.; The operation a mod ba\bmod b computes the remainder of aa divided by bb.