Rewriting the PDE as a dot product with the gradient allows the equation to be interpreted as a statement about directional derivatives. Specifically, it shows that the directional derivative of u in the direction (5,2) is zero, which implies that u is constant along curves in that direction.
Conditions: The PDE is 5ux+2uy=0.; ∇u is the gradient vector (ux,uy).
Rewriting the PDE as a dot product with the gradient allows the equation to be interpreted as a statement about directional derivatives. Specifically, it shows that the directional derivative of u in the direction (5,2) is zero, which implies that u is constant along curves in that direction.
Conditions: The PDE is 5ux+2uy=0.; ∇u is the gradient vector (ux,uy).
To expand (5,2)·∇u, substitute ∇u=(ux,uy) and apply the definition of the Euclidean dot product: multiply corresponding components and add them. This yields 5ux+2uy.
Conditions: ∇u=(ux,uy).; The dot product is defined as the sum of the products of corresponding components.
To expand (5,2)·∇u, substitute ∇u=(ux,uy) and apply the definition of the Euclidean dot product: multiply corresponding components and add them. This yields 5ux+2uy.
Conditions: ∇u=(ux,uy).; The dot product is defined as the sum of the products of corresponding components.
The gradient ∇u is the vector whose components are the first partial derivatives of u. For a function of two variables, ∇u=(ux,uy), where ux is the partial derivative with respect to x and uy is the partial derivative with respect to y.
Conditions: u is a scalar function of two variables x and y.; u has partial derivatives with respect to x and y.
The gradient ∇u is the vector whose components are the first partial derivatives of u. For a function of two variables, ∇u=(ux,uy), where ux is the partial derivative with respect to x and uy is the partial derivative with respect to y.
Conditions: u is a scalar function of two variables x and y.; u has partial derivatives with respect to x and y.