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Answers for “为什么模 n 的整数恰好有 n 个元素并且仍然构成循环群?”

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To show that the integers Z\mathbb{Z} under addition are cyclic, demonstrate that Z=⟨1⟩\mathbb{Z} = \langle 1 \rangle. The subgroup generated by 11 contains 11, its inverse −1-1, the identity 00, and all integer multiples of 11, which exhausts all integers.

Conditions: The group is Z\mathbb{Z} with operation ++.; The candidate generator is 11.

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A group generated by one element is called cyclic because the elements of the generated subgroup can be viewed as cycling through powers (or multiples) of the generator. In finite cases like Z/nZ\mathbb{Z}/n\mathbb{Z}, the sequence of multiples of the generator repeats periodically, forming a cycle.

Conditions: The group is generated by a single element.; In the finite case, the modulus nn determines the length of the cycle.