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Answers for “为什么 a_1 大于 a_2 意味着有更多的 1/(2π) 赫兹频率?”

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Understand why

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In the displayed Fourier-series setup, a1a_1 is the coefficient for cos⁡(t)\cos(t), which corresponds to the base frequency of 12π\frac{1}{2\pi} hertz. a2a_2 is the coefficient for cos⁡(2t)\cos(2t), corresponding to 1π\frac{1}{\pi} hertz.

Conditions: The function is represented in the displayed form with cosine coefficients a1,a2,a3a_1, a_2, a_3.; The comparison is about the coefficients multiplying cos⁡(t)\cos(t) and cos⁡(2t)\cos(2t).

Meet the concept

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The coefficients a1a_1 and b1b_1 act as weights that tell how much each component is involved in the function. If a1a_1 is much larger than b1b_1, the function has more cosine of tt than sine of tt.

Conditions: The series is being constructed as a weighted sum of sines and cosines.; The coefficients are real-valued.

Meet the concept

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If the base period is 2π2\pi, the term cos⁡(t)\cos(t) has a frequency of 12π\frac{1}{2\pi} cycles per second. Doubling the argument to cos⁡(2t)\cos(2t) doubles the frequency, so cos⁡(2t)\cos(2t) has a frequency of 1π\frac{1}{\pi} cycles per second.

Conditions: The base period of the function is 2π2\pi.; The frequency is defined as the reciprocal of the period.