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Answers for “为什么 u \otimes v 满足这些分配律和标量移动规则?”

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Understand why

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The tensor product notation u⊗vu \otimes v satisfies distributive laws and scalar mobility rules because it is constructed via a bilinear map φ\varphi. Bilinearity implies linearity in each variable separately, leading to (a1u1+a2u2)⊗v=a1u1⊗v+a2u2⊗v(a_1u_1+a_2u_2)\otimes v=a_1u_1\otimes v+a_2u_2\otimes v, u⊗(b1v1+b2v2)=b1u⊗v1+b2u⊗v2u\otimes(b_1v_1+b_2v_2)=b_1u\otimes v_1+b_2u\otimes v_2, and a(u⊗v)=(au)⊗v=u⊗(av)a(u\otimes v)=(au)\otimes v=u\otimes(av).

Conditions: u,u1,u2u, u_1, u_2 belong to UU.; v,v1,v2v, v_1, v_2 belong to VV.; a,a1,a2,b1,b2a, a_1, a_2, b_1, b_2 are scalars in the field P\mathbb{P}.

Meet the concept

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The notation U⊗VU \otimes V denotes the entire tensor product space, which is uniquely determined up to isomorphism. In contrast, u⊗vu \otimes v denotes a basic tensor element within that space, generated by applying the bilinear map φ\varphi to vectors u∈Uu \in U and v∈Vv \in V.

Conditions: UU and VV are linear spaces over the number field P\mathbb{P}.; uu is in UU and vv is in VV.; φ\varphi is the bilinear map in the tensor product construction.

Understand why

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The Kronecker product A⊗BA \otimes B is an mp×nqmp \times nq block matrix because it replaces each element aija_{ij} of the m×nm \times n matrix AA with the p×qp \times q matrix aijBa_{ij}B. This results in mm row blocks and nn column blocks, each of size p×qp \times q, making the total dimensions mp×nqmp \times nq.

Conditions: AA is an m×nm \times n matrix.; BB is a p×qp \times q matrix.; aija_{ij} is an element of AA.