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Answers for “在二元公式中,插值和逼近有什么区别?”

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In the bivariate formulation, interpolation requires the fitted function to match the measured values exactly at every given data point, expressed as zi=F(xi,yi)z_i = F(x_i, y_i). Approximation relaxes this exact fitting by allowing a deviation or error term e(xi,yi)e(x_i, y_i), expressed as zi=F(xi,yi)+e(xi,yi)z_i = F(x_i, y_i) + e(x_i, y_i).

Conditions: Given m points (xi,yi,zi)(x_i, y_i, z_i) with i=1,mi=1,m.; Find a function F(x,y)F(x,y).; Interpolation requires exact matching at the sample points.; Approximation allows an error term e(xi,yi)e(x_i, y_i).

Understand why

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The groundwater example requires quadrivariate interpolation because the observations are scattered in three-dimensional space and also vary over time. This involves four variables: three spatial dimensions and time.

Conditions: Input values are measured at 3D points over time.; Output is a 4D raster combining 3D space and time.

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Bivariate interpolation is the process of finding a surface representation based on values measured at 2D points. Its main applications include converting scattered points, profiles, or isolines into a raster format, computing a denser or smoother Triangulated Irregular Network (TIN), and resampling continuous-data rasters, such as elevation, to a higher resolution.

Conditions: Input values are measured at 2D points.; Output is a surface representation, raster, or denser/smoothed TIN.

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In the “surface points in time” visualization, the vertical axis represents the distribution in time, not the actual three-dimensional physical location or depth. Each point still has an x, y horizontal location, but the plotted vertical extent encodes elapsed time, as illustrated by lengths corresponding to 250 days and around 500 days.

Conditions: The visualization is the left panel labeled “surface points in time”.; The data represents groundwater measurements over time.