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Answers for “在这个余弦级数例子中,为什么可以交换求和与积分?”

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Understand why

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The sum and integral can be interchanged because the Dominated Convergence Theorem applies. The terms of the cosine power series are bounded in magnitude by 11 on the interval [0,π/2][0,\pi/2], making the constant function g(x)=1g(x)=1 a valid dominating function with a finite integral over the interval.

Conditions: The integration interval is [0,π/2][0,\pi/2].; The series terms are (−1)n(2n)!x2n\frac{(-1)^n}{(2n)!}x^{2n}.; The dominating function is g(x)=1g(x)=1.

Find a method

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The integral is computed by substituting the Maclaurin series for cos⁡x\cos x, using the DCT to interchange the sum and integral, integrating each monomial term using the power rule, simplifying the factorial denominator, recognizing the resulting series as the sine series, and evaluating it at the endpoints 00 and π/2\pi/2.

Conditions: The integration interval is [0,π/2][0,\pi/2].; The cosine power series is cos⁡x=∑n=0∞(−1)n(2n)!x2n\cos x = \sum_{n=0}^{\infty} \frac{(-1)^n}{(2n)!} x^{2n}.; The DCT is applicable because the series terms are dominated by g(x)=1g(x)=1 on [0,π/2][0,\pi/2].

Meet the concept

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The DCT justifies exchanging the definite integral over [a,b][a,b] with the infinite summation, allowing term-by-term integration. Specifically, it establishes that ∫ab∑fn(x) dx=∑∫abfn(x) dx\int_a^b \sum f_n(x)\,dx = \sum \int_a^b f_n(x)\,dx.

Conditions: The previously stated convergence, domination, and finite-integral conditions are assumed to hold.; The summation is over the sequence of functions fnf_n.; The integration is over the closed interval [a,b][a,b].