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Answers for “如何使用点斜式公式写出直线方程?”

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To find the point on the curve y=x2−4y = x^2 - 4 at x=−1x = -1, substitute x=−1x = -1 into the equation. Evaluating (−1)2−4(-1)^2 - 4 yields 1−4=−31 - 4 = -3, so the coordinates of the point are (−1,−3)(-1, -3).

Conditions: The curve is defined by the equation y=x2−4y = x^2 - 4.; The x-coordinate of the desired point is given as −1-1.; The point must lie on the curve.