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Answers for “如何使用边界条件 u(0,y)=sin y 确定任意函数 f?”

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The general solution is u(x,y)=f(y−(2/5)x)u(x,y) = f(y - (2/5)x), where f is an arbitrary differentiable function of one variable. This form arises because u is constant along the characteristic curves y=(2/5)x+cy = (2/5)x + c, so u depends only on the invariant c=y−(2/5)xc = y - (2/5)x.

Conditions: u is constant along the characteristic curves.; f is an arbitrary function of one variable.