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Answers for “如何将 R^4 中的一般向量分解为 W 中的向量与 W^perp 中的向量之和?”

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A general vector in R4\mathbb{R}^4 is decomposed by separating its coordinates into two blocks. The first two coordinates form a vector in WW, and the last two coordinates form a vector in W⊥W^\perp.

Conditions: The ambient space is R4\mathbb{R}^4.; WW has basis {(1000),(0100)}\left\{\begin{pmatrix}1\\0\\0\\0\end{pmatrix},\begin{pmatrix}0\\1\\0\\0\end{pmatrix}\right\}.; W⊥W^\perp has basis {(0010),(0001)}\left\{\begin{pmatrix}0\\0\\1\\0\end{pmatrix},\begin{pmatrix}0\\0\\0\\1\end{pmatrix}\right\}.; The vector is represented as (abcd)\begin{pmatrix}a\\b\\c\\d\end{pmatrix} with a,b,c,d∈Ra,b,c,d \in \mathbb{R}.

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The lecturer states that the representation is unique because, in the context of a direct sum W⊕W⊥=R4W \oplus W^\perp = \mathbb{R}^4, there is only one way to split a given vector into a part belonging to WW and a part belonging to W⊥W^\perp. No other pair of vectors from these subspaces can sum to the same original vector.

Conditions: The ambient space is R4\mathbb{R}^4.; WW and W⊥W^\perp are the specific subspaces defined on the board.; The equation W⊕W⊥=R4W \oplus W^\perp = \mathbb{R}^4 holds.

Meet the concept

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The example defines a subspace WW spanned by the first two standard basis vectors of R4\mathbb{R}^4, and its orthogonal complement W⊥W^\perp spanned by the last two standard basis vectors. Together, they form a direct sum that equals the entire space R4\mathbb{R}^4.

Conditions: The ambient space is R4\mathbb{R}^4.; The bases are taken as given on the board.