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Factoring and cancelling resolves the limit by simplifying the expression to a form that is defined near the target point. For $x \ne 2$ near 2, the expression $\frac{x^2+3x-10}{x^2-2x}$ factors into $\frac{(x-2)(x+5)}{x(x-2)}$.

Conditions: The limit is as $x \to 2$.; The original expression is undefined at $x=2$ (indeterminate form $0/0$).; Cancellation is valid only for $x \ne 2$.

Factoring and cancelling resolves the limit by simplifying the expression to a form that is defined near the target point. For $x \ne 2$ near 2, the expression $\frac{x^2+3x-10}{x^2-2x}$ factors into $\frac{(x-2)(x+5)}{x(x-2)}$.

Conditions: The limit is as $x \to 2$.; The original expression is undefined at $x=2$ (indeterminate form $0/0$).; Cancellation is valid only for $x \ne 2$.