Skip to content
START WITH A QUESTION

What would you like to understand?

Find an answer. See the moment it becomes clear. Follow the idea further.

← Concept directory

Answers for “对于常微分方程 $\ddot{x}+3\dot{x}+2x=2e^{-t}$,为什么特解使用 $Ate^{-t}$ 而不是 $Ae^{-t}$?”

2 keyword matches

Understanding your question. You can explore the search results below now.

Understand why

↗

The particular solution uses Ate−tAte^{-t} because the forcing term e−te^{-t} is already a solution to the associated homogeneous equation. In the method of undetermined coefficients, if the forcing function overlaps with a homogeneous solution (resonance), the standard guess must be multiplied by tt to ensure linear independence.

Conditions: The ODE is linear with constant coefficients.; The forcing term contains e−te^{-t}.; r=−1r=-1 is a root of the homogeneous characteristic equation.

Find a method

↗

The homogeneous roots are obtained by solving the associated homogeneous equation x¨+3x˙+2x=0\ddot{x}+3\dot{x}+2x=0. By substituting the exponential trial solution x=ertx=e^{rt}, the differential equation converts into the characteristic polynomial r2+3r+2=0r^2+3r+2=0, which factors to (r+2)(r+1)=0(r+2)(r+1)=0, yielding the roots r=−2r=-2 and r=−1r=-1.

Conditions: The ODE has constant coefficients.; The trial solution is of the form x=ertx=e^{rt}.; The characteristic equation is a quadratic polynomial.