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Answers for “映射 ga = a 是群作用吗?”

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Yes, the map ga=aga = a for all g∈Gg \in G and a∈Aa \in A is a group action, known as the trivial action. It satisfies both the compatibility and identity properties of a group action.

Conditions: GG is a group and AA is a set.; The map is defined by ga=aga = a for all g∈Gg \in G and a∈Aa \in A.

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To verify if a map is a group action, first check that its domain is G×AG \times A and its codomain is AA. Then, verify the two properties: g1⋅(g2⋅a)=(g1g2)⋅ag_1 \cdot (g_2 \cdot a) = (g_1 g_2) \cdot a for all g1,g2∈Gg_1, g_2 \in G and a∈Aa \in A, and 1⋅a=a1 \cdot a = a for all a∈Aa \in A.

Conditions: The map is defined from G×AG \times A to AA.; GG is a group and AA is a set.

Meet the concept

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A group action of a group GG on a set AA is a map from G×AG \times A to AA, written as g⋅ag \cdot a, that satisfies two properties: compatibility with the group operation (g1⋅(g2⋅a)=(g1g2)⋅ag_1 \cdot (g_2 \cdot a) = (g_1 g_2) \cdot a) and the identity property (1⋅a=a1 \cdot a = a).

Conditions: GG is a group.; AA is a set.; The action is a map from G×AG \times A to AA.; Property (a) holds for all g1,g2∈Gg_1, g_2 \in G and a∈Aa \in A.; Property (b) holds for all a∈Aa \in A.