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The video concludes $X$ is compact because it demonstrates that an open cover $C$ of the finite space $X$ has a finite subcover $C_1$. The speaker applies the definition of compactness (every open cover has a finite subcover) to this finite setting.

Conditions: $X$ is finite.; Compactness is defined by the requirement that every open cover of $X$ has a finite subcover.

The video concludes $X$ is compact because it demonstrates that an open cover $C$ of the finite space $X$ has a finite subcover $C_1$. The speaker applies the definition of compactness (every open cover has a finite subcover) to this finite setting.

Conditions: $X$ is finite.; Compactness is defined by the requirement that every open cover of $X$ has a finite subcover.

No, showing one open cover with a finite subcover does not prove compactness for all covers. Compactness requires that *every* open cover has a finite subcover.

Conditions: The context is the definition of compactness.; The demonstration is limited to a single chosen open cover.

No, showing one open cover with a finite subcover does not prove compactness for all covers. Compactness requires that *every* open cover has a finite subcover.

Conditions: The context is the definition of compactness.; The demonstration is limited to a single chosen open cover.