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Answers for “Prim 算法的时间复杂度是多少?”

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The time complexity of Prim's algorithm depends on the data structures used. Using an adjacency matrix with searching gives O(V2)O(V^2), while using a binary heap with an adjacency list gives O(Vlog⁡V+Elog⁡V)O(V \log V + E \log V), where VV is the number of vertices and EE is the number of edges.

Conditions: The graph is represented using specific data structures.; VV denotes the number of vertices.; EE denotes the number of edges.

Understand why

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Edge B-E is skipped because both of its endpoints (B and E) are already in the visited set (MST). Prim's algorithm only considers edges that connect a visited vertex to an unvisited vertex to avoid creating cycles.

Conditions: Both endpoints of the edge are already marked as visited.; The algorithm strictly follows the rule of adding only crossing edges.

Meet the concept

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Dijkstra's algorithm is a method for finding the shortest path from a single starting node to all other nodes in a weighted directed graph. It is distinct from minimum spanning tree algorithms like Prim's and Kruskal's, which connect all nodes with the minimum total edge weight rather than finding paths from a specific source.

Conditions: The graph must be weighted.; The graph can be directed or undirected, though the video primarily demonstrates it on a directed graph.

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No, the minimum spanning tree is not always unique. It is unique only if all edge weights in the graph are distinct.

Conditions: The graph is weighted.; Uniqueness is guaranteed only when all edge weights are pairwise distinct.

Find a method

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To compute the total weight of the MST, sum the weights of all edges that were selected and added to the tree during the execution of Prim's algorithm.

Conditions: The MST edge set has been fully determined.; You have access to the weights of the selected edges.

Meet the concept

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A minimum spanning tree (MST) is a connected, acyclic subgraph that spans all vertices of a weighted graph and has the minimum possible total edge weight.

Conditions: The underlying graph must be weighted.; The graph must be connected for a spanning tree to exist.; The MST minimizes the sum of selected edge weights.; The MST contains no cycles.