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The final equation of the secant line intersecting the curve $y = x^2 - 4$ at $x = -1$ and $x = 2$ is $y = x - 2$. This result is derived by calculating the slope $m = 1$ between the points $(-1, -3)$ and $(2, 0)$, then applying the point-slope formula and simplifying to slope-intercept form.

Conditions: The curve is $y = x^2 - 4$.; The secant line intersects the curve at $x = -1$ and $x = 2$.; The equation is expressed in slope-intercept form ($y = mx + b$).

The final equation of the secant line intersecting the curve $y = x^2 - 4$ at $x = -1$ and $x = 2$ is $y = x - 2$. This result is derived by calculating the slope $m = 1$ between the points $(-1, -3)$ and $(2, 0)$, then applying the point-slope formula and simplifying to slope-intercept form.

Conditions: The curve is $y = x^2 - 4$.; The secant line intersects the curve at $x = -1$ and $x = 2$.; The equation is expressed in slope-intercept form ($y = mx + b$).

To find the x-intercepts of the curve $y = x^2 - 4$, set the function equal to zero ($x^2 - 4 = 0$) and factor the expression as a difference of squares into $(x+2)(x-2) = 0$. Applying the zero-product property yields the solutions $x = -2$ and $x = 2$, which are the points where the graph crosses the x-axis.

Conditions: The curve is defined by the quadratic equation $y = x^2 - 4$.; The goal is to find where the graph crosses the x-axis.; The algebraic method used is factoring the difference of perfect squares.

To find the x-intercepts of the curve $y = x^2 - 4$, set the function equal to zero ($x^2 - 4 = 0$) and factor the expression as a difference of squares into $(x+2)(x-2) = 0$. Applying the zero-product property yields the solutions $x = -2$ and $x = 2$, which are the points where the graph crosses the x-axis.

Conditions: The curve is defined by the quadratic equation $y = x^2 - 4$.; The goal is to find where the graph crosses the x-axis.; The algebraic method used is factoring the difference of perfect squares.